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A Recurring Decimal Problem

Dr Barker 2,610 lượt xem 5 months ago
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Given ab.cabcab... = p.qppqpp... + q.qqq... (in base 10), we find the possible values of a, b, c, p, and q.

00:00 Values of a
01:10 a = 0
04:20 b = p + q + 1
07:22 b = p + q
08:52 10 + b = p + q + 1
14:12 10 + b = p + q

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