How to evaluate the indefinite integral 1/(Sin²Θ)dΘ | Integrate 1/(Sin^2(x))dx | calculus

In this video I explain how to evaluate the indefinite integral 1/(Sin²Θ)dΘ, ∫1/(Sin²Θ)dΘ. I demonstrate how to manipulate 1/(Sin²Θ) and use a trig identity to replace the denominator. I then use U-substitution and use a further trig identity to simplify the integral. I then evaluate the integral and substitute back in for U.