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Proof: Limit of sinx/x as x approaches 0 with Squeeze Theorem | Calculus 1

Wrath of Math 40,542 2 years ago
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We prove the limit of sinx/x as x goes to 0 equals 1 using the squeeze theorem and a geometric argument involving sectors and triangles on the unit circle. #calculus1 #apcalculus Join Wrath of Math to get exclusive videos, lecture notes, and more: https://www.youtube.com/channel/UCyEKvaxi8mt9FMc62MHcliw/join Squeeze Theorem Explained: (coming soon) Limit of (1-cosx)/x: https://youtu.be/4hX_WEmf9j4 Get the textbook for this course! https://amzn.to/3PieD1M ★DONATE★ ◆ Support Wrath of Math on Patreon: https://www.patreon.com/join/wrathofmathlessons ◆ Donate on PayPal: https://www.paypal.me/wrathofmath Follow Wrath of Math on... ● Instagram: https://www.instagram.com/wrathofmathedu ● TikTok: https://www.tiktok.com/@wrathofmathedu ● X: https://x.com/wrathofmathedu ● Facebook: https://www.facebook.com/WrathofMath

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