In this video, we continue the discussion of finding (x,y) pairs that will commute under exponentiation: x^y = y^x. This time, we will find another way of writing Euler's number and solve the equation x^y = y^x for y with the help of the Lambert W function.
Ideas were adapted from the following paper:
http://www.ww.amc12.org/sites/default/files/pdf/upload_library/22/Chauvenet/Knoebelchv.pdf